f(x)=1/2+x x>0 1+e的x次方 x

来源:学生作业帮助网 编辑:作业帮 时间:2024/11/15 02:34:45
f(x)=1/2+x x>0 1+e的x次方 x
x)KӨд57ҮP3P0N}>ٚϦTI*'DΆ(suV6յ3U*5TH<ٽȵ-IM))yg!P!X"YW.c`a Ԇ[ԠtKNm.R#mn]C7F 1m0'1%-RҊADb1"Nw

f(x)=1/2+x x>0 1+e的x次方 x
f(x)=1/2+x x>0 1+e的x次方 x

f(x)=1/2+x x>0 1+e的x次方 x
∫ [0-->2] f(x-1) dx
令x-1=t,dx=dt,t:-1-->1
=∫ [-1-->1] f(t) dt
=∫ [-1-->0] 1/(2+t) dt+∫ [0-->1] (1+e^t) dt
=ln|2+t| | [-1-->0] +(t+e^t) | [0-->1]
=ln2+1+e-1
=ln2+e

adfasfasdfsasdfas