方程(m-1)x²+(m²-1)x-m=0的两根互为倒数,则m= ;若两根互为相反数,则m= ;一根为0,则m=
来源:学生作业帮助网 编辑:作业帮 时间:2024/08/02 07:00:39
![方程(m-1)x²+(m²-1)x-m=0的两根互为倒数,则m= ;若两根互为相反数,则m= ;一根为0,则m=](/uploads/image/z/5177974-22-4.jpg?t=%E6%96%B9%E7%A8%8B%28m-1%29x%26%23178%3B%2B%28m%26%23178%3B-1%29x-m%3D0%E7%9A%84%E4%B8%A4%E6%A0%B9%E4%BA%92%E4%B8%BA%E5%80%92%E6%95%B0%2C%E5%88%99m%3D+%3B%E8%8B%A5%E4%B8%A4%E6%A0%B9%E4%BA%92%E4%B8%BA%E7%9B%B8%E5%8F%8D%E6%95%B0%2C%E5%88%99m%3D+%3B%E4%B8%80%E6%A0%B9%E4%B8%BA0%2C%E5%88%99m%3D)
x){6mjʆHH7';<[ɮIOvz0
:O;f*X^,|HOv4$w2$R;]=AY`19ZFͺ`DMϵ57B5n'XPh$@͂%K.~{֥@980$l@A
方程(m-1)x²+(m²-1)x-m=0的两根互为倒数,则m= ;若两根互为相反数,则m= ;一根为0,则m=
方程(m-1)x²+(m²-1)x-m=0的两根互为倒数,则m= ;若两根互为相反数,则m= ;一根为0,则m=
方程(m-1)x²+(m²-1)x-m=0的两根互为倒数,则m= ;若两根互为相反数,则m= ;一根为0,则m=
二根为倒数
则有x1*x2=1
即-m/(m-1)=1
得m=1/2
二根为相反数
x1+x2=0
即-(m²-1)/(m-1)=0
-(m+1)=0
得m=-1
一根为0代入得
m=0