x^2+y^2=8,x^2-4xy+3y^2=0的方程组的解
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x^2+y^2=8,x^2-4xy+3y^2=0的方程组的解
x^2+y^2=8,x^2-4xy+3y^2=0的方程组的解
x^2+y^2=8,x^2-4xy+3y^2=0的方程组的解
由x^2-4xy+3y^2=0
得(x-3y)(x-y)=0
x=3y (1)
x=y (2)
(1)代入x^2+y^2=8 10y^2=8 y=±2√5/5
所以x1=6√5/5 y1=2√5/5
x2=-6√5/5 y2=-2√5/5
(2)代入x^2+y^2=8 2y^2=8 y=±2
所以x3=2 y3=2
x4=-2 y4=-2
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