如图,三角形ABC中,角ACB=90度,CD垂直于AB于D,AE平分角CAB,AE交CD于点F.求证:CE=CF.
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![如图,三角形ABC中,角ACB=90度,CD垂直于AB于D,AE平分角CAB,AE交CD于点F.求证:CE=CF.](/uploads/image/z/5179607-71-7.jpg?t=%E5%A6%82%E5%9B%BE%2C%E4%B8%89%E8%A7%92%E5%BD%A2ABC%E4%B8%AD%2C%E8%A7%92ACB%3D90%E5%BA%A6%2CCD%E5%9E%82%E7%9B%B4%E4%BA%8EAB%E4%BA%8ED%2CAE%E5%B9%B3%E5%88%86%E8%A7%92CAB%2CAE%E4%BA%A4CD%E4%BA%8E%E7%82%B9F.%E6%B1%82%E8%AF%81%EF%BC%9ACE%3DCF.)
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