(x-2y+3z)(x-3z-2y)=
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(x-2y+3z)(x-3z-2y)=
(x-2y+3z)(x-3z-2y)=
(x-2y+3z)(x-3z-2y)=
解
(x-2y+3z)(x-3z-2y)
=[(x-2y)+3z][(x-2y)-3z]
=(x-2y)²-(3z)²
=x²-4xy+4y²-9z²
x^2 -3xz -2xy -2xy +6yz +4y^2 +3xz -9z^2 -6yz
=x^2 - 4xy +4y^2 -9z^2
(x-2y+3z)(x-3z-2y)
=((x-2y)+3z)((x-2y)-3z)
=(x-2y)²-(3z)²
=x²-4xy+4y²-9z²
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