已知丨x+1丨+(y+2)²+丨z-1丨=0,求(x+y)²-(y+z)²-(z+x)²
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已知丨x+1丨+(y+2)²+丨z-1丨=0,求(x+y)²-(y+z)²-(z+x)²
已知丨x+1丨+(y+2)²+丨z-1丨=0,求(x+y)²-(y+z)²-(z+x)²
已知丨x+1丨+(y+2)²+丨z-1丨=0,求(x+y)²-(y+z)²-(z+x)²
丨x+1丨+(y+2)²+丨z-1丨=0,
则
丨x+1丨=0,x=-1
(y+2)²=0,y=-2
丨z-1丨=0,z=1
求(x+y)²-(y+z)²-(z+x)²=9-1-0=8
8 x=-1,y=-2,z=1