若x²-y²=1且x＞0,y＞0,求x√(1+y²)-y√(x²-1)的值

来源：学生作业帮助网 编辑：作业帮 时间：2024/07/06 17:42:36
若x²-y²=1且x＞0,y＞0,求x√(1+y²)-y√(x²-1)的值
x){ѽBMZB>1y:`ƦG4 *4u+A|>CZ6I*ҧyv6wS-x6c~qAbj

若x²-y²=1且x＞0,y＞0,求x√(1+y²)-y√(x²-1)的值
若x²-y²=1且x＞0,y＞0,求x√(1+y²)-y√(x²-1)的值

若x²-y²=1且x＞0,y＞0,求x√(1+y²)-y√(x²-1)的值
答案是1