已知(a²+b²)(a²+b²-8)+16=0,求a²+b²的值
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已知(a²+b²)(a²+b²-8)+16=0,求a²+b²的值
已知(a²+b²)(a²+b²-8)+16=0,求a²+b²的值
已知(a²+b²)(a²+b²-8)+16=0,求a²+b²的值
令x=a²+b²
则x(x-8)+16=0
x²-8x+16=0
(x-4)²=0
x-4=0
x=4
所以a²+b²=4