若关于x的方程x²-(a²+b²-6b)x+a²+b²-4b+2a+1=0,的两个实数根x1,x满足 x1≤0≤x2≤1,则a²+b²+4a的最大值和最小值分别为?
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![若关于x的方程x²-(a²+b²-6b)x+a²+b²-4b+2a+1=0,的两个实数根x1,x满足 x1≤0≤x2≤1,则a²+b²+4a的最大值和最小值分别为?](/uploads/image/z/5187918-30-8.jpg?t=%E8%8B%A5%E5%85%B3%E4%BA%8Ex%E7%9A%84%E6%96%B9%E7%A8%8Bx%26%23178%3B-%EF%BC%88a%26%23178%3B%2Bb%26%23178%3B-6b%EF%BC%89x%2Ba%26%23178%3B%2Bb%26%23178%3B-4b%2B2a%2B1%3D0%2C%E7%9A%84%E4%B8%A4%E4%B8%AA%E5%AE%9E%E6%95%B0%E6%A0%B9x1%2Cx%E6%BB%A1%E8%B6%B3+x1%E2%89%A40%E2%89%A4x2%E2%89%A41%2C%E5%88%99a%26%23178%3B%2Bb%26%23178%3B%2B4a%E7%9A%84%E6%9C%80%E5%A4%A7%E5%80%BC%E5%92%8C%E6%9C%80%E5%B0%8F%E5%80%BC%E5%88%86%E5%88%AB%E4%B8%BA%3F)
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