tan1/2θ-tan1/2θ/1=-2/tanθ求证
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tan1/2θ-tan1/2θ/1=-2/tanθ求证
tan1/2θ-tan1/2θ/1=-2/tanθ求证
tan1/2θ-tan1/2θ/1=-2/tanθ求证
令a=1/2θ
左边=tana-1/tana
=(tan²a-1)/tana
=-2/[2tana/(1-tan²a)]
=-2/tan2a
=-2/tanθ