计算,sin25π/6+cos25π/3+tan(-25π/4)
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计算,sin25π/6+cos25π/3+tan(-25π/4)
计算,sin25π/6+cos25π/3+tan(-25π/4)
计算,sin25π/6+cos25π/3+tan(-25π/4)
原式=sin(4π+π/6)+cos(8π+π/3)+tan(-6π-π/4)
=sin(π/6)+cos(π/3)+tan(-π/4)
=1/2+1/2-1
=0
计算:sin25π/6+cos25π/4+tan(-25π/4)+sin(-26π/3)
计算,sin25π/6+cos25π/3+tan(-25π/4)
sin25π/6+cos25π/3+tan(-25π/4)
先估计结果的符号,再进行计算sin25π/6+cos25π/3+tan(- 25π/4)
sin25π/6 + cos25π/3 + tan(-25π/4)这题怎么算?
求sin25π/6+cos25π/3+tan(-25π/4)的值?
一道很基础的三角函数化简题sin25π/6+cos25π/3+tan25π/4 化简:
sin25π/6+cos25π/3+tan25π/4等于多少?
计算sin25∏/6+cos25∏/3+tan(-25∏/4)急用!
sin25π/4+cos25π/3+tan(-25π/4)=
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sin25π÷6+cos25π÷3+tan(-25π÷4)是怎么计算的?我比较笨,请写出详细过程,感谢各位回答者!在线等!
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