作业帮判断y=lg[(tanx+1)/(tanx-1)]的奇偶性
来源：学生作业帮助网 编辑：作业帮 时间：2024/11/06 05:48:24
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判断y=lg[(tanx+1)/(tanx-1)]的奇偶性
判断y=lg[(tanx+1)/(tanx-1)]的奇偶性
判断y=lg[(tanx+1)/(tanx-1)]的奇偶性
令f(x)=lg[(tanx+1)/(tanx-1)]
f(-x)=lg[(tan(-x)+1)/(tan(-x)-1)]
=lg[(tanx-1)/(tanx+1)]
=-lg[tanx+1)/(tanx-1)]
所以是奇函数