解数学一元二次方程(1-根号2)x²=(1+根号2)x25(3x-2)²=(2x-3)²x²-(2+根号2)x+根号2-根号3=0
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![解数学一元二次方程(1-根号2)x²=(1+根号2)x25(3x-2)²=(2x-3)²x²-(2+根号2)x+根号2-根号3=0](/uploads/image/z/5201907-51-7.jpg?t=%E8%A7%A3%E6%95%B0%E5%AD%A6%E4%B8%80%E5%85%83%E4%BA%8C%E6%AC%A1%E6%96%B9%E7%A8%8B%EF%BC%881-%E6%A0%B9%E5%8F%B72%EF%BC%89x%26%23178%3B%3D%EF%BC%881%2B%E6%A0%B9%E5%8F%B72%EF%BC%89x25%EF%BC%883x-2%EF%BC%89%26%23178%3B%3D%EF%BC%882x-3%EF%BC%89%26%23178%3Bx%26%23178%3B-%EF%BC%882%2B%E6%A0%B9%E5%8F%B72%EF%BC%89x%2B%E6%A0%B9%E5%8F%B72-%E6%A0%B9%E5%8F%B73%3D0)
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解数学一元二次方程(1-根号2)x²=(1+根号2)x25(3x-2)²=(2x-3)²x²-(2+根号2)x+根号2-根号3=0
解数学一元二次方程
(1-根号2)x²=(1+根号2)x
25(3x-2)²=(2x-3)²
x²-(2+根号2)x+根号2-根号3=0
解数学一元二次方程(1-根号2)x²=(1+根号2)x25(3x-2)²=(2x-3)²x²-(2+根号2)x+根号2-根号3=0
怎麽这麽难,用求根公式
两边同时乘以(1+根号2) X=-1/3+2根号2 {[5(3x-2)]²-(2x-3)²}=0 (15x-10)²-(2x-3)²=0 (15x-10-2x+3)(15x-10+2x-3)=0 x=7/13 or 13/17
用求根公式啊