如图,CD垂直AB,EF垂直AB,垂足分别为D,F,角E等于角EMC,求证:CD是角ACB的角平分线 图画的不好见谅!
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![如图,CD垂直AB,EF垂直AB,垂足分别为D,F,角E等于角EMC,求证:CD是角ACB的角平分线 图画的不好见谅!](/uploads/image/z/5204548-28-8.jpg?t=%E5%A6%82%E5%9B%BE%2CCD%E5%9E%82%E7%9B%B4AB%2CEF%E5%9E%82%E7%9B%B4AB%2C%E5%9E%82%E8%B6%B3%E5%88%86%E5%88%AB%E4%B8%BAD%2CF%2C%E8%A7%92E%E7%AD%89%E4%BA%8E%E8%A7%92EMC%2C%E6%B1%82%E8%AF%81%3ACD%E6%98%AF%E8%A7%92ACB%E7%9A%84%E8%A7%92%E5%B9%B3%E5%88%86%E7%BA%BF+%E5%9B%BE%E7%94%BB%E7%9A%84%E4%B8%8D%E5%A5%BD%E8%A7%81%E8%B0%85%21)
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