已知sin(a+B)sin(a-B)=1/3,求cos2b-cos2a
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已知sin(a+B)sin(a-B)=1/3,求cos2b-cos2a
已知sin(a+B)sin(a-B)=1/3,求cos2b-cos2a
已知sin(a+B)sin(a-B)=1/3,求cos2b-cos2a
cos2b-cos2a
=cos[(a+b)-(a-b)]-cos[(a+b)+(a-b)]
=[cos(a+b)cos(a-b)+sin(a+b)sin(a-b)]-
[cos(a+b)cos(a-b)-sin(a+b)sin(a-b)]
=2sin(a+b)sin(a-b)
=2/3
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3 在三角形ABC中,已知(a2+b2)sin(A-B)=(a2-b2)sin(A+B) 求证:ABC是等腰或直角三角形(a^2+b^2)sin(A-B)=(a^2-b^2)sin(A+B),(sin^A+sin^B)sin(A-B)=(sin^A-sin^B)sin(A+B) sin^A*(sin(A+B)-sin(A-B))=sin^B*(sin(A-B)+sin(A+B)) sin^A*2c
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已知sin(a+B)sin(a-B)=1/3,求cos2b-cos2a
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