已知化学方程式:H2O(g)=H2+1/2O2(g) AH=+241.8KJ/molH2(g)+1/2O2(g)=H2O(l) AH=-285.8KJ/mol当1g液态水变为蒸汽时,其热量变化是多少?请求答疑?
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![已知化学方程式:H2O(g)=H2+1/2O2(g) AH=+241.8KJ/molH2(g)+1/2O2(g)=H2O(l) AH=-285.8KJ/mol当1g液态水变为蒸汽时,其热量变化是多少?请求答疑?](/uploads/image/z/521523-27-3.jpg?t=%E5%B7%B2%E7%9F%A5%E5%8C%96%E5%AD%A6%E6%96%B9%E7%A8%8B%E5%BC%8F%EF%BC%9AH2O%28g%29%3DH2%2B1%2F2O2%28g%29+AH%3D%2B241.8KJ%2FmolH2%28g%29%2B1%2F2O2%28g%29%3DH2O%28l%29+AH%3D-285.8KJ%2Fmol%E5%BD%931g%E6%B6%B2%E6%80%81%E6%B0%B4%E5%8F%98%E4%B8%BA%E8%92%B8%E6%B1%BD%E6%97%B6%2C%E5%85%B6%E7%83%AD%E9%87%8F%E5%8F%98%E5%8C%96%E6%98%AF%E5%A4%9A%E5%B0%91%3F%E8%AF%B7%E6%B1%82%E7%AD%94%E7%96%91%3F)
已知化学方程式:H2O(g)=H2+1/2O2(g) AH=+241.8KJ/molH2(g)+1/2O2(g)=H2O(l) AH=-285.8KJ/mol当1g液态水变为蒸汽时,其热量变化是多少?请求答疑?
已知化学方程式:
H2O(g)=H2+1/2O2(g) AH=+241.8KJ/mol
H2(g)+1/2O2(g)=H2O(l) AH=-285.8KJ/mol
当1g液态水变为蒸汽时,其热量变化是多少?
请求答疑?
已知化学方程式:H2O(g)=H2+1/2O2(g) AH=+241.8KJ/molH2(g)+1/2O2(g)=H2O(l) AH=-285.8KJ/mol当1g液态水变为蒸汽时,其热量变化是多少?请求答疑?
H2(g)+ 1/2O2(g) = H2O(g)△H1 = -241.8 KJ/mol (1)
H2(g)+ 1/2O2(g) = H2O(l) △H2 =-285.8 KJ/mol ……(2)
-241.8 -285.8 ==44KJ
1g水的物质的量为1/18mol
44/18=2.44KJ
设:H2O(g) = H2 + 1/2O2(g) △H1 = +241.8 KJ/mol …… (1)
H2(g)+ 1/2O2(g) = H2O(l) △H2 =-285.8 KJ/mol ……(2)
反应(2)— 反应(1)得:
H2O(l) → H2O(g) △H3
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设:H2O(g) = H2 + 1/2O2(g) △H1 = +241.8 KJ/mol …… (1)
H2(g)+ 1/2O2(g) = H2O(l) △H2 =-285.8 KJ/mol ……(2)
反应(2)— 反应(1)得:
H2O(l) → H2O(g) △H3
△H3 = △H2 — △H1 = -285.8KJ/mol — 241.8 KJ/mol = -527.6 KJ/mol
1g液态水变为蒸汽时,其热量变化为:
-527.6 KJ/mol ÷ 18g/mol ×1g = -29.3 KJ
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