4x/(x²+x+3) + 5x/(x²-5x+3)= - 3/2

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4x/(x²+x+3) + 5x/(x²-5x+3)= - 3/2
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4x/(x²+x+3) + 5x/(x²-5x+3)= - 3/2
4x/(x²+x+3) + 5x/(x²-5x+3)= - 3/2

4x/(x²+x+3) + 5x/(x²-5x+3)= - 3/2
分母变为x+1+3/x和x-5+3/x
还是换元法:令x+3/x=y
则原方程化为4/(y+1)+5/(y-5)=-3/2
解出y
回代到x+3/x=y
解出x