a/b = 1-x/y 求b/a(a)x/(y-x)(b)y/x-1(c)y/(x-y)(d)x/y + 1(e)y/(y-x)第2题(3y-1)(2y+k) = ay的平方+by-5求a+b等于多少

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a/b = 1-x/y 求b/a(a)x/(y-x)(b)y/x-1(c)y/(x-y)(d)x/y + 1(e)y/(y-x)第2题(3y-1)(2y+k) = ay的平方+by-5求a+b等于多少
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a/b = 1-x/y 求b/a(a)x/(y-x)(b)y/x-1(c)y/(x-y)(d)x/y + 1(e)y/(y-x)第2题(3y-1)(2y+k) = ay的平方+by-5求a+b等于多少
a/b = 1-x/y 求b/a
(a)x/(y-x)
(b)y/x-1
(c)y/(x-y)
(d)x/y + 1
(e)y/(y-x)
第2题
(3y-1)(2y+k) = ay的平方+by-5
求a+b等于多少

a/b = 1-x/y 求b/a(a)x/(y-x)(b)y/x-1(c)y/(x-y)(d)x/y + 1(e)y/(y-x)第2题(3y-1)(2y+k) = ay的平方+by-5求a+b等于多少
1.(e)
(3y-1)(2y+k) = ay^2+by-5
6y^2+(3k-2)y-k=ay^2+by-5
a=6,k=5 3k-2=b
a=6 b=13
a+b=19

1.a/b=1-x/y=(y-x)/y b/a=y/(y-x) 2.(3y-1)(3y+k)=9y的平方+(3K-3)y-k=ay的平方+by-5 /9=a < 3k-3=b \k=5 a=9 b=12 a+b=21 把分给我吧!谢谢了!

楼上的题目没看清吧把2y看成3y了,其他的都一样,a+b=19.第一题我感觉没答案,从正负判断就可以了