(1)已知A={a+2,(a+1)²,a²+3a+3}且1∈A,求实数a的值(2)已知M+{2,a,b},N={2a,2,b²}且M=N,求a,b的值.3.已知集合A={x丨-2≤x≤3},B={x>a}(1)若A交B=空集.求实数a的取值范围(2)若A交B=A,求实数a的取
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![(1)已知A={a+2,(a+1)²,a²+3a+3}且1∈A,求实数a的值(2)已知M+{2,a,b},N={2a,2,b²}且M=N,求a,b的值.3.已知集合A={x丨-2≤x≤3},B={x>a}(1)若A交B=空集.求实数a的取值范围(2)若A交B=A,求实数a的取](/uploads/image/z/5222749-13-9.jpg?t=%EF%BC%881%EF%BC%89%E5%B7%B2%E7%9F%A5A%3D%7Ba%2B2%2C%28a%2B1%29%26sup2%3B%2Ca%26sup2%3B%2B3a%2B3%7D%E4%B8%941%E2%88%88A%2C%E6%B1%82%E5%AE%9E%E6%95%B0a%E7%9A%84%E5%80%BC%EF%BC%882%EF%BC%89%E5%B7%B2%E7%9F%A5M%2B%7B2%2Ca%2Cb%7D%2CN%3D%7B2a%2C2%2Cb%26sup2%3B%7D%E4%B8%94M%3DN%2C%E6%B1%82a%2Cb%E7%9A%84%E5%80%BC.3.%E5%B7%B2%E7%9F%A5%E9%9B%86%E5%90%88A%3D%7Bx%E4%B8%A8-2%E2%89%A4x%E2%89%A43%7D%2CB%3D%7Bx%EF%BC%9Ea%7D%281%29%E8%8B%A5A%E4%BA%A4B%3D%E7%A9%BA%E9%9B%86.%E6%B1%82%E5%AE%9E%E6%95%B0a%E7%9A%84%E5%8F%96%E5%80%BC%E8%8C%83%E5%9B%B4%EF%BC%882%EF%BC%89%E8%8B%A5A%E4%BA%A4B%3DA%2C%E6%B1%82%E5%AE%9E%E6%95%B0a%E7%9A%84%E5%8F%96)
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(1)已知A={a+2,(a+1)²,a²+3a+3}且1∈A,求实数a的值(2)已知M+{2,a,b},N={2a,2,b²}且M=N,求a,b的值.3.已知集合A={x丨-2≤x≤3},B={x>a}(1)若A交B=空集.求实数a的取值范围(2)若A交B=A,求实数a的取
(1)已知A={a+2,(a+1)²,a²+3a+3}且1∈A,求实数a的值
(2)已知M+{2,a,b},N={2a,2,b²}且M=N,求a,b的值.
3.已知集合A={x丨-2≤x≤3},B={x>a}
(1)若A交B=空集.求实数a的取值范围
(2)若A交B=A,求实数a的取值范围
(1)已知A={a+2,(a+1)²,a²+3a+3}且1∈A,求实数a的值(2)已知M+{2,a,b},N={2a,2,b²}且M=N,求a,b的值.3.已知集合A={x丨-2≤x≤3},B={x>a}(1)若A交B=空集.求实数a的取值范围(2)若A交B=A,求实数a的取
1.
假设a+2=1
=》a=-1
那么a²+3a+3=1,集合A中有两个1,假设不成立
假设a²+3a+3=1,=》a=-1或-2,
分别会导致a+2=1和(a+1)²=1,因此也会造成集合A有两个1,假设不成立
因此:(a+1)²=1
=》a=0
2.
因为M=N
假设a=b^,则b=2a=2b^2,=>b=0,a=0,假设不成立
=》a=2a,=》a=0
=》b=b^2 =>b=1(因为a已经=0)
因此a=0,b=1
3.
(1)因为对A有x<=3,对B有x>a,
因此A交B=空集=》a>=3
(2)
因为x>=-2
因此a<=-2