已知α是第三象限角,且f(α)=[sin(π-α)cos(2π-α)]/sin(3π-α)1.化简f(α)2.若sinα=-3/5,求f(α)3.若α=-1860°,求f(α)

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已知α是第三象限角,且f(α)=[sin(π-α)cos(2π-α)]/sin(3π-α)1.化简f(α)2.若sinα=-3/5,求f(α)3.若α=-1860°,求f(α)
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已知α是第三象限角,且f(α)=[sin(π-α)cos(2π-α)]/sin(3π-α)1.化简f(α)2.若sinα=-3/5,求f(α)3.若α=-1860°,求f(α)
已知α是第三象限角,且f(α)=[sin(π-α)cos(2π-α)]/sin(3π-α)
1.化简f(α)
2.若sinα=-3/5,求f(α)
3.若α=-1860°,求f(α)

已知α是第三象限角,且f(α)=[sin(π-α)cos(2π-α)]/sin(3π-α)1.化简f(α)2.若sinα=-3/5,求f(α)3.若α=-1860°,求f(α)
1.f(α)=[sin(π-α)cos(2π-α)]/sin(3π-α)=sinacosa/sina=cosa
2.α是第三象限角,sinα=-3/5,cosa=-4/5,f(α)=-4/5
3.f(α)=cos(-1860°)=cos1860°=cos60°=1/2

不就是化简求值吗?学了数学必修四的人必须会的,你也太懒了吧