已知m =(2cosx+2 3 sinx,1),n =(cosx,-y)已知m =(2cosx+2 3 sinx,1), \x05n =(cosx,-y)
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![已知m =(2cosx+2 3 sinx,1),n =(cosx,-y)已知m =(2cosx+2 3 sinx,1), \x05n =(cosx,-y)](/uploads/image/z/5227355-11-5.jpg?t=%E5%B7%B2%E7%9F%A5m+%3D%282cosx%2B2+3+sinx%2C1%29%2Cn+%3D%28cosx%2C-y%29%E5%B7%B2%E7%9F%A5m+%3D%282cosx%2B2+3+sinx%2C1%29%2C+%5Cx05n+%3D%28cosx%2C-y%29)
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已知m =(2cosx+2 3 sinx,1),n =(cosx,-y)已知m =(2cosx+2 3 sinx,1), \x05n =(cosx,-y)
已知m =(2cosx+2 3 sinx,1),n =(cosx,-y)
已知m =(2cosx+2
3 sinx,1), \x05n =(cosx,-y)
已知m =(2cosx+2 3 sinx,1),n =(cosx,-y)已知m =(2cosx+2 3 sinx,1), \x05n =(cosx,-y)
加油,你可以的,跟我期中考考试的题目很像哈哈.