sinα=1-m cosα=1-2m,tan α=

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sinα=1-m cosα=1-2m,tan α=
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sinα=1-m cosα=1-2m,tan α=
sinα=1-m cosα=1-2m,tan α=

sinα=1-m cosα=1-2m,tan α=
sin²a+cos²a=1,则:
(1-m)²+(1-2m)²=1,解得:m=1或m=1/5
1、当m=1时,sina=0,cosa=1,则tana=0;
2、当m=1/5时,sina=4/5,cosa=3/5,则tana=sina/cosa=4/3

(1-m)/(1-2m)

tana=sina/cosa=(1-m)/(1-2m)

sin²α+cos²α=1
所以1-2m+m²+1-4m+4m²=1
5m²-6m+1=0
(5m-1)(m-1)=0
m=1/5,m=1
所以sinα=4/5,cosα=3/5
sinα=0,cosα=-1
tanα=sinα/cosα=4/3或0

tan α = sinα/cosα = (1-m)/(1-2m)