已知a²+b²-10a-6b+34=0,求(a-b/a+b)²÷a²-b²/ab×a²+2ab+b²/a²-b²的值
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已知a²+b²-10a-6b+34=0,求(a-b/a+b)²÷a²-b²/ab×a²+2ab+b²/a²-b²的值
已知a²+b²-10a-6b+34=0,
求(a-b/a+b)²÷a²-b²/ab×a²+2ab+b²/a²-b²的值
已知a²+b²-10a-6b+34=0,求(a-b/a+b)²÷a²-b²/ab×a²+2ab+b²/a²-b²的值
a^2+b^2-10a-6b+34=0
a^2-10a+b^2-6b=-34
a^2-10a+25+b^2-6b+9=-34+25+9
(a-5)^2+(b-3)^2=0
∵和等于0
(a-5)^2≥0,(b-3)^2≥0
∴a-5=0,b-3=0
a=5,b=3
下面的求值,代数式可以写清楚一些吗?需要看成一个整体的,请加上括号
- -各种看不懂
a²+b²-10a-6b+34=0 因式分解可以得到(a-5)的平方+(b-3)的平方=0 所以a=5 b=3 剩下的只要把a b 代到式子里就可以了。