已知:(ay-bx)²+(bz-cy)²+(cx-az)²=0.求证:x/a+y/b+z/c.
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已知:(ay-bx)²+(bz-cy)²+(cx-az)²=0.求证:x/a+y/b+z/c.
已知:(ay-bx)²+(bz-cy)²+(cx-az)²=0.求证:x/a+y/b+z/c.
已知:(ay-bx)²+(bz-cy)²+(cx-az)²=0.求证:x/a+y/b+z/c.
因为(ay-bx)²+(bz-cy)²+(cx-az)²=0
所以ax-by=0 bz-cy=0 cx-az=0
所以ax=by bz=cy cx=az
所以x/a=y/b=z/c