定义在R上的偶函数f(x),满足f(x+1)=-f(x),且在区间【-1,0】上递增,则 ()A.f(3)<f(√2)<f(2) B.f(2)<f(3)<f(√2) C.f(3)<f(2)<f(√2) D.f(√2)<f(2)<f(3) ,我自己有做但不明白哪错了,f(3)=f(2+1)=-f(2) f(2)=f(
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![定义在R上的偶函数f(x),满足f(x+1)=-f(x),且在区间【-1,0】上递增,则 ()A.f(3)<f(√2)<f(2) B.f(2)<f(3)<f(√2) C.f(3)<f(2)<f(√2) D.f(√2)<f(2)<f(3) ,我自己有做但不明白哪错了,f(3)=f(2+1)=-f(2) f(2)=f(](/uploads/image/z/5242777-25-7.jpg?t=%E5%AE%9A%E4%B9%89%E5%9C%A8R%E4%B8%8A%E7%9A%84%E5%81%B6%E5%87%BD%E6%95%B0f%28x%29%2C%E6%BB%A1%E8%B6%B3f%28x%2B1%29%3D-f%28x%29%2C%E4%B8%94%E5%9C%A8%E5%8C%BA%E9%97%B4%E3%80%90-1%2C0%E3%80%91%E4%B8%8A%E9%80%92%E5%A2%9E%2C%E5%88%99+%EF%BC%88%EF%BC%89A.f%283%29%EF%BC%9Cf%28%E2%88%9A2%29%EF%BC%9Cf%282%29+B.f%282%29%EF%BC%9Cf%283%29%EF%BC%9Cf%28%E2%88%9A2%29+C.f%283%29%EF%BC%9Cf%282%29%EF%BC%9Cf%28%E2%88%9A2%29+D.f%28%E2%88%9A2%29%EF%BC%9Cf%282%29%EF%BC%9Cf%283%29+%2C%E6%88%91%E8%87%AA%E5%B7%B1%E6%9C%89%E5%81%9A%E4%BD%86%E4%B8%8D%E6%98%8E%E7%99%BD%E5%93%AA%E9%94%99%E4%BA%86%2Cf%283%29%3Df%282%2B1%29%3D-f%282%29+f%282%29%3Df%28)
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