2x-1/2[x-1/2(x-1)]=2/3(x-1)
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2x-1/2[x-1/2(x-1)]=2/3(x-1)
2x-1/2[x-1/2(x-1)]=2/3(x-1)
2x-1/2[x-1/2(x-1)]=2/3(x-1)
去括号,再解
原式=2X-1/2X-1/4X-1/2.
x=-5/13
x=-5/13
2 2
2x-0.5[x-0.5x+0.5]=-x--
3 3
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x/x-2+x-9/x-7=x+1/x-1+x-8/x-6,
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