作业帮解不等式log(0.5)(x2-5x-6)＞log(2)(1/2(x+6))
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解不等式log(0.5)(x2-5x-6)＞log(2)(1/2(x+6))
解不等式log(0.5)(x2-5x-6)＞log(2)(1/2(x+6))
解不等式log(0.5)(x2-5x-6)＞log(2)(1/2(x+6))
log(0.5)(x²-5x-6)>log2(1/2(x+6))
log2[1/(x²-5x-6)]>log2[1/2(x+6)]
1/(x²-5x-6)>1/2(x+6)
x²-5x-6<2(x+6)
x²-7x-18<0
(x-9)(x+2)<0
-2
(x-6)(x+1)>0
-1
x>-6
综合起来
-1
底数1/2<1 所以log1/2^N是减函数所以(x+1)(6-x)<12 (x-6)(x+1)>-12 x^2-5x+6>0 (x-2)(x-3)>0 x>3,x<2 结合定义域 -1
解不等式log(0.5)(x2-5x-6)＞log(2)(1/2(x+6))
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