把(x-y),(a+b)作为一个因式,合并同类项.(1)3(x-y)^2-9(x-y)-8(x-y)^2+6(x-y)-1为什么我的出来的是:(1)原式=-5(x-y)^2 +3(x-y) -1
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![把(x-y),(a+b)作为一个因式,合并同类项.(1)3(x-y)^2-9(x-y)-8(x-y)^2+6(x-y)-1为什么我的出来的是:(1)原式=-5(x-y)^2 +3(x-y) -1](/uploads/image/z/5246060-68-0.jpg?t=%E6%8A%8A%28x-y%29%2C%28a%2Bb%29%E4%BD%9C%E4%B8%BA%E4%B8%80%E4%B8%AA%E5%9B%A0%E5%BC%8F%2C%E5%90%88%E5%B9%B6%E5%90%8C%E7%B1%BB%E9%A1%B9.%281%293%28x-y%29%5E2-9%28x-y%29-8%28x-y%29%5E2%2B6%28x-y%29-1%E4%B8%BA%E4%BB%80%E4%B9%88%E6%88%91%E7%9A%84%E5%87%BA%E6%9D%A5%E7%9A%84%E6%98%AF%EF%BC%9A%EF%BC%881%EF%BC%89%E5%8E%9F%E5%BC%8F%3D-5%28x-y%29%5E2+%2B3%28x-y%29+-1)
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把(x-y),(a+b)作为一个因式,合并同类项.(1)3(x-y)^2-9(x-y)-8(x-y)^2+6(x-y)-1为什么我的出来的是:(1)原式=-5(x-y)^2 +3(x-y) -1
把(x-y),(a+b)作为一个因式,合并同类项.(1)3(x-y)^2-9(x-y)-8(x-y)^2+6(x-y)-1
为什么我的出来的是:
(1)
原式=-5(x-y)^2 +3(x-y) -1
把(x-y),(a+b)作为一个因式,合并同类项.(1)3(x-y)^2-9(x-y)-8(x-y)^2+6(x-y)-1为什么我的出来的是:(1)原式=-5(x-y)^2 +3(x-y) -1
(1)3(x-y)^2-9(x-y)-8(x-y)^2+6(x-y)-1
=(3-8)(x-y)²-(9-6)(x-y)-1
=-5(x-y)²-3(x-y)-1
你的答案是错的.