计算:a/(a+1)^2+1/(a+1)^2 ,2x/x^2+64y^2-1/x-8y
来源:学生作业帮助网 编辑:作业帮 时间:2024/07/12 09:39:17
![计算:a/(a+1)^2+1/(a+1)^2 ,2x/x^2+64y^2-1/x-8y](/uploads/image/z/5248734-6-4.jpg?t=%E8%AE%A1%E7%AE%97%3Aa%2F%28a%2B1%29%5E2%2B1%2F%28a%2B1%29%5E2+%2C2x%2Fx%5E2%2B64y%5E2-1%2Fx-8y)
x){nuӭ5
5㌴
a,
Ie~EMR>zln-B%bgЀhjTh[T )Єp 4*tX6Axyv x`q
计算:a/(a+1)^2+1/(a+1)^2 ,2x/x^2+64y^2-1/x-8y
计算:a/(a+1)^2+1/(a+1)^2 ,2x/x^2+64y^2-1/x-8y
计算:a/(a+1)^2+1/(a+1)^2 ,2x/x^2+64y^2-1/x-8y
计算:a/(a+1)^2+1/(a+1)^2 =(a+1)/(a+1)^2=1/(a+1)
,2x/x^2-64y^2-1/x-8y
=2x/(x^2-64y^2)-(x+8y)/(x-8y)(x+8y)
=(2x-x-8y)/(x-8y)(x+8y)
=1/(x+8y)