(x+3y-16):(2x-2y+16):(2x+y+4)=1;2:3 解方程.
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(x+3y-16):(2x-2y+16):(2x+y+4)=1;2:3 解方程.
(x+3y-16):(2x-2y+16):(2x+y+4)=1;2:3 解方程.
(x+3y-16):(2x-2y+16):(2x+y+4)=1;2:3 解方程.
解析:
已知:(x+3y-16):(2x-2y+16):(2x+y+4)=1:2:3,那么:
(x+3y-16)/(2x-2y+16)=1/2
即2(x+3y-16)=2x-2y+16
2x+6y-32=2x-2y+16
8y=48
解得y=6
而(x+3y-16):(2x+y+4)=1:3
那么:3(x+3y-16)=2x+y+4
即3x+9y-48=2x+y+4
x=-8y+52=4
所以原方程的解为:x=4,y=6 (经检验,满足题意)
令x+3y-16=k
则有:
2x-2y+16=2k=2(x+3y-16)=2x+6y-32
整理得:
8y=48
y=6
2x+y+4=3k=3(x+3y-16)=3x+9y-48
整理得:
x+8y=52
将y=6代入,得:
x=4
故原方程组的解是:
x=4 y=6【记得拿大括号括上】
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