求lim(x->2)[(x+2)/(x^2+3x-10)]的极限.答案是无穷大(横着的8的符号).我想要具体的步骤!希望懂的人帮帮忙.还有一题:lim(x->0)[1-(1+2^2)]/x^2 (1+2^2)这个是有根号的,我手机打不出来,将就看了,知道就行.这
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![求lim(x->2)[(x+2)/(x^2+3x-10)]的极限.答案是无穷大(横着的8的符号).我想要具体的步骤!希望懂的人帮帮忙.还有一题:lim(x->0)[1-(1+2^2)]/x^2 (1+2^2)这个是有根号的,我手机打不出来,将就看了,知道就行.这](/uploads/image/z/5252608-64-8.jpg?t=%E6%B1%82lim%28x-%3E2%29%5B%28x%2B2%29%2F%28x%5E2%2B3x-10%29%5D%E7%9A%84%E6%9E%81%E9%99%90.%E7%AD%94%E6%A1%88%E6%98%AF%E6%97%A0%E7%A9%B7%E5%A4%A7%28%E6%A8%AA%E7%9D%80%E7%9A%848%E7%9A%84%E7%AC%A6%E5%8F%B7%29.%E6%88%91%E6%83%B3%E8%A6%81%E5%85%B7%E4%BD%93%E7%9A%84%E6%AD%A5%E9%AA%A4%21%E5%B8%8C%E6%9C%9B%E6%87%82%E7%9A%84%E4%BA%BA%E5%B8%AE%E5%B8%AE%E5%BF%99.%E8%BF%98%E6%9C%89%E4%B8%80%E9%A2%98%3Alim%28x-%3E0%29%5B1-%281%2B2%5E2%29%5D%2Fx%5E2+%281%2B2%5E2%29%E8%BF%99%E4%B8%AA%E6%98%AF%E6%9C%89%E6%A0%B9%E5%8F%B7%E7%9A%84%2C%E6%88%91%E6%89%8B%E6%9C%BA%E6%89%93%E4%B8%8D%E5%87%BA%E6%9D%A5%2C%E5%B0%86%E5%B0%B1%E7%9C%8B%E4%BA%86%2C%E7%9F%A5%E9%81%93%E5%B0%B1%E8%A1%8C.%E8%BF%99)
求lim(x->2)[(x+2)/(x^2+3x-10)]的极限.答案是无穷大(横着的8的符号).我想要具体的步骤!希望懂的人帮帮忙.还有一题:lim(x->0)[1-(1+2^2)]/x^2 (1+2^2)这个是有根号的,我手机打不出来,将就看了,知道就行.这
求lim(x->2)[(x+2)/(x^2+3x-10)]的极限.
答案是无穷大(横着的8的符号).我想要具体的步骤!希望懂的人帮帮忙.还有一题:lim(x->0)[1-(1+2^2)]/x^2 (1+2^2)这个是有根号的,我手机打不出来,将就看了,知道就行.这题的答案是 (-1/2)
求lim(x->2)[(x+2)/(x^2+3x-10)]的极限.答案是无穷大(横着的8的符号).我想要具体的步骤!希望懂的人帮帮忙.还有一题:lim(x->0)[1-(1+2^2)]/x^2 (1+2^2)这个是有根号的,我手机打不出来,将就看了,知道就行.这
说明:第二题有错误,正确的是lim(x->0)[(1-√(1+x²))/x²].
lim(x->2)[(x+2)/(x²+3x-10)]=lim(x->2)[(x+2)/((x-2)(x+5))]
=(2+2)/((2-2)(2+5))
=4/(0*7)
=4/0
=∞;
lim(x->0)[(1-√(1+x²))/x²]=lim(x->0)[((1-√(1+x²))(1+√(1+x²)))/(x²(1+√(1+x²)))] (分子有理化)
=lim(x->0)[(1-(1+x²))/(x²(1+√(1+x²)))]
=lim(x->0)[(-x²)/(x²(1+√(1+x²)))]
=lim(x->0)[(-1)/(1+√(1+x²))]
=[(-1)/(1+√(1+0²))]
=-1/2.
4/0->∞
第二个没法将就着看
lim(x->2)[(x+2)/(x^2+3x-10)] = 4/0 = 无穷大