如下图,已知定圆F1:x²+y²+10x+24=0,定圆F2:x²+y²-10x+9=0,…………如下图,已知定圆F1:x²+y²+10x+24=0,定圆F2:x²+y²-10x+9=0,动圆M与定圆F1,F2都外切,求动圆圆心M的轨迹方程
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![如下图,已知定圆F1:x²+y²+10x+24=0,定圆F2:x²+y²-10x+9=0,…………如下图,已知定圆F1:x²+y²+10x+24=0,定圆F2:x²+y²-10x+9=0,动圆M与定圆F1,F2都外切,求动圆圆心M的轨迹方程](/uploads/image/z/5253411-3-1.jpg?t=%E5%A6%82%E4%B8%8B%E5%9B%BE%2C%E5%B7%B2%E7%9F%A5%E5%AE%9A%E5%9C%86F1%3Ax%26%23178%3B%2By%26%23178%3B%2B10x%2B24%3D0%2C%E5%AE%9A%E5%9C%86F2%3Ax%26%23178%3B%2By%26%23178%3B-10x%2B9%3D0%2C%E2%80%A6%E2%80%A6%E2%80%A6%E2%80%A6%E5%A6%82%E4%B8%8B%E5%9B%BE%2C%E5%B7%B2%E7%9F%A5%E5%AE%9A%E5%9C%86F1%3Ax%26%23178%3B%2By%26%23178%3B%2B10x%2B24%3D0%2C%E5%AE%9A%E5%9C%86F2%3Ax%26%23178%3B%2By%26%23178%3B-10x%2B9%3D0%2C%E5%8A%A8%E5%9C%86M%E4%B8%8E%E5%AE%9A%E5%9C%86F1%2CF2%E9%83%BD%E5%A4%96%E5%88%87%2C%E6%B1%82%E5%8A%A8%E5%9C%86%E5%9C%86%E5%BF%83M%E7%9A%84%E8%BD%A8%E8%BF%B9%E6%96%B9%E7%A8%8B)
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如下图,已知定圆F1:x²+y²+10x+24=0,定圆F2:x²+y²-10x+9=0,…………如下图,已知定圆F1:x²+y²+10x+24=0,定圆F2:x²+y²-10x+9=0,动圆M与定圆F1,F2都外切,求动圆圆心M的轨迹方程
如下图,已知定圆F1:x²+y²+10x+24=0,定圆F2:x²+y²-10x+9=0,…………
如下图,已知定圆F1:x²+y²+10x+24=0,定圆F2:x²+y²-10x+9=0,动圆M与定圆F1,F2都外切,求动圆圆心M的轨迹方程
如下图,已知定圆F1:x²+y²+10x+24=0,定圆F2:x²+y²-10x+9=0,…………如下图,已知定圆F1:x²+y²+10x+24=0,定圆F2:x²+y²-10x+9=0,动圆M与定圆F1,F2都外切,求动圆圆心M的轨迹方程
(x+5)²+y²=1
C1(-5,0),r1=1
(x-5)²+y²=16
C2(5,0),r2=4
设M(x,y)
外切则圆心距等于半径和
则MC1=r+1
MC2=r+4
MC2-MC1=3
所以是双曲线,2a=3
a=3/2
c=5
b²=25-9/4=91/4
4x²/9-4y²/91=1
MC2>MC1
所以是左支
所以4x²/9-4y²/91=1,x<0