根号(x+1)(-x²+x+2)(x<-1)化简
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根号(x+1)(-x²+x+2)(x<-1)化简
根号(x+1)(-x²+x+2)(x<-1)
化简
根号(x+1)(-x²+x+2)(x<-1)化简
√[(x+1)(-x²+x+2)]
=√[(x+1)(2-x)(1+x)]
=|1+x|√(2-x)
=-(1+x)√(2-x)
∵x<-1,
∴x+1<0,x-2<0
根号(x+1)(-x²+x+2)
=根号[-(x+1)(x²-x-2)]
=根号[-(x+1)(x+1)(x-2)]
=根号[-(x+1)²(x-2)]
=根号[(x+1)²(2-x)]
=|x+1|根号(2-x)
=-(x+1)根号(2-x)