解方程:1/(x-1)(x-2)=1/(x-4)(x-5)
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解方程:1/(x-1)(x-2)=1/(x-4)(x-5)
解方程:1/(x-1)(x-2)=1/(x-4)(x-5)
解方程:1/(x-1)(x-2)=1/(x-4)(x-5)
同取倒数就是(x-1)(x-2)=(x-4)(x-5)
x^2+2-3x=x^2+20-9x
9x-3x=20-2
6x=18
x=3
两边开括号即可.得X=3
同学到数学百事通去问老师,是专业老师在解
由题,(x-1)(x-2)=(x-4)(x-5)
乘出来,x^2-3x+2=x^2-9x+20
所以,6x=18
所以,x=3
由1/【(x-1)(x-2)】=1/【(x-4)(x-5)】得,(x-1)(x-2)=(x-4)(x-5),解得x=3.