函数f(x)定义在正整数集上,且满足:f(1)=2008和f(1)+f(2)+···+f(n)=n2f(n),则f(2008)的值是---------.可否解释得容易点,让我好明白,我刚高一,谢谢
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![函数f(x)定义在正整数集上,且满足:f(1)=2008和f(1)+f(2)+···+f(n)=n2f(n),则f(2008)的值是---------.可否解释得容易点,让我好明白,我刚高一,谢谢](/uploads/image/z/5258099-11-9.jpg?t=%E5%87%BD%E6%95%B0f%28x%29%E5%AE%9A%E4%B9%89%E5%9C%A8%E6%AD%A3%E6%95%B4%E6%95%B0%E9%9B%86%E4%B8%8A%2C%E4%B8%94%E6%BB%A1%E8%B6%B3%3Af%281%29%3D2008%E5%92%8Cf%281%29%2Bf%282%29%2B%C2%B7%C2%B7%C2%B7%2Bf%28n%29%3Dn2f%28n%29%2C%E5%88%99f%282008%29%E7%9A%84%E5%80%BC%E6%98%AF---------.%E5%8F%AF%E5%90%A6%E8%A7%A3%E9%87%8A%E5%BE%97%E5%AE%B9%E6%98%93%E7%82%B9%2C%E8%AE%A9%E6%88%91%E5%A5%BD%E6%98%8E%E7%99%BD%2C%E6%88%91%E5%88%9A%E9%AB%98%E4%B8%80%2C%E8%B0%A2%E8%B0%A2)
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