已知x+2y+3y=10,4x+3y+2z=15,求x+y+z的值
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已知x+2y+3y=10,4x+3y+2z=15,求x+y+z的值
已知x+2y+3y=10,4x+3y+2z=15,求x+y+z的值
已知x+2y+3y=10,4x+3y+2z=15,求x+y+z的值
根据已知的两个等式,将这两个等式左侧和右侧分别相加,即(x+2y+3z)+(4x+3y+2z)=10+15,合并同类项可得:5x+5y+5z=25,两边同除以5,即可得x+y+z=5
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