(m+1)x²+2mx+(m-1)=0
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(m+1)x²+2mx+(m-1)=0
(m+1)x²+2mx+(m-1)=0
(m+1)x²+2mx+(m-1)=0
(m+1)x²+2mx+(m-1)=0
[(m+1)x+1][x+(m-1)]=0
x1=-1/(m+1),x2=1-m
(m+1)x^2+2mx+(m-1)=0
x=[-2m±根号下(4m^2-4(m+1)(m-1)]/2(m+1)
x=(-2m±根号4)/2(m+1)
x=(-2m±2)/2(m+1)
x1=`(-m+1)/(m+1)
x2=-1