作业帮确定函数f(x)=log1/2[根号2*sin(x-pai/4)]的单调区间
来源：学生作业帮助网 编辑：作业帮 时间：2024/07/17 04:53:12
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确定函数f(x)=log1/2[根号2*sin(x-pai/4)]的单调区间
确定函数f(x)=log1/2[根号2*sin(x-pai/4)]的单调区间
确定函数f(x)=log1/2[根号2*sin(x-pai/4)]的单调区间
由题意知sin(x-π/4)>0
则x-π/4∈(2kπ,π+2kπ),k∈Z
因为底数1/2
f(x)=log1/2[根号2*sin(x-pai/4)]
=-1/2-log2 sin(x-pai/4)
0
此时3π/4<=x<5π/4