(a-2b+3c)(a+2b-3c)=
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(a-2b+3c)(a+2b-3c)=
(a-2b+3c)(a+2b-3c)=
(a-2b+3c)(a+2b-3c)=
原式=[a-(2b-3c)][a+(2b-3c)]
=a²-(2b-3c)²
=a²-(4b²-12bc+9c²)
=a²-4b²+12bc-9c²
原式=[a-(2b-3c)][a+(2b-3c)]
=a²-(2b-3c)²
=a²-(4b²-12bc+9c²)
=a²-4b²+12bc-9c²我们老师是这么教的。
(a-2b+3c)(a+2b-3c)
=a²-(2b-3c)²
=a²-4b²+12bc-9c²
原式=[a-(2b-3c)][a+(2b-3c)]
=a²-(2b-3c)²
=a²-(4b²-12bc+9c²)
=a²-4b²+12bc-9c²
=[a-(2b-3c)][a+(2b-3c)]
=a^2-(2b-3c)^2
=a^2-(4b^2+9c^2-12bc)
=a^2-4b^2-9c^2+12bc
3a-c=4a+2b-c=a+b+c a:b:c
(a-b+c/a+b-c)-(a-2b+3c/b-c+a)+(b-2c/c-a-b)
已知:(a-b)(b-c)(c-a)/(a+b)(b+c)(c+a)=5/132,求a/(a+b)+b/(b+c)+c/(c+a)的值!(请尽快,我有急用,a/(a+b)+b/(b+c)+c/(c+a)=1/2[(a-b)/(a+b)+(b-c)/(b+c)+(c-a)/(c+a)]+3/2 (a-b)/(a+b)+(b-c)/(b+c)+(c-a)/(c+a) 没有错吧...
(a-b)(b-c)(c-a)/(b-a)(a-c)2(c-b)3
2a(a+b-c)-3b(a+b-c)+5c(c-a-b)
a=3b,c=2a*3,a+b+c*a+b-c=?
2a(b-c)+3(c-b)
2a-(3b+c-b)=(2a-c)-()
化简|a-b|-2c-|c+b|+|3b| c
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设A.B.C均为正数,求证c/(a+b)+a/(b+c)+b/(c+a)>=3/2
b+c-2a)^3+(c+a-2b)^3+(a+b-2c)^3=(b+c-2a)(c+a-2b)(a+b-2c)求证(b+c-2a)^3+(c+a-2b)^3+(a+b-2c)^3=(b+c-2a)(c+a-2b)(a+b-2c)
a-b=5,b-c=3,(c-a)(2b-a-c)=
1/a=2/b=3/c求a+b-c/a-b+c=?
(a-b-c)X( b+c-a)^2X(c-a+b)^3=?
化简:7(a-b-c)-5(a+b-c)+3(a-b-c)+(a+b-2)
(2a-b)(3b-c)=