在△ABC,AB=AC,BD平分∠ABC交AC边于点D,∠BDC为75°,则∠A的度数为 求讲解
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![在△ABC,AB=AC,BD平分∠ABC交AC边于点D,∠BDC为75°,则∠A的度数为 求讲解](/uploads/image/z/5271720-24-0.jpg?t=%E5%9C%A8%E2%96%B3ABC%2CAB%3DAC%2CBD%E5%B9%B3%E5%88%86%E2%88%A0ABC%E4%BA%A4AC%E8%BE%B9%E4%BA%8E%E7%82%B9D%2C%E2%88%A0BDC%E4%B8%BA75%C2%B0%2C%E5%88%99%E2%88%A0A%E7%9A%84%E5%BA%A6%E6%95%B0%E4%B8%BA+%E6%B1%82%E8%AE%B2%E8%A7%A3)
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