x+2y+3z=14 2x+y+z=7 3x+y+2z=11 求XYZ

x+y+z=14 7z=x+y+2 x+z=y 试证明(x+y-2z)+(y+z-2x)+(z+x-2y)=3(x+y-2z)(y+z-2x)(z+x-2y) 已知(x+y)(x+z)=x,(y+z)(y+x)=2y,(z+x)(z+y)=3z,求x,y,z x+y+z=6 x+2y+3z=14 y+1=z (1)X+Y=15,Y+Z=-6,Z+X=7.(2)X+Y=-14,Y+Z=-7,Z+X=9.(3)X+Y=0,Y+Z=-1,Z+X=-1. x+2y+3z=14 2x+y+z=7 3x+y+2z=11 解方程：x+z=y (1) ,7z-(x+y)=2 (2) ,x+y+z=14 (3) x+2y+3z=14 2x+y+z=7 3x+y+2z=11 求x y z x+2y+3z=14 2x+y+z=7 3x+y+2z=11 求x y z 证明 ：x/(y+z)+y/(z+x)+z/(x+y)>=3/2其中 x,y,z>0 {x+y+z=1;x+3y+7z=-1;z+5y+8z=-2 x/2=y/3=z/5 x+3y-z/x-3y+z x+2y=3x+2z=4y+z 求x:y:z x+y/2=z+x/3=y+z/4 x+y+z=27 若x+y+z=3y=2z,则x/x+y+z=? fangchengzu:X+Z=Y 7Z=X+Y+Z X+Y+Z=14 用行列式的性质证明：y+z z+x x+y x y z x+y y+z z+x =2 z x y z+x x+y y+z y z x 这个怎么证? (x-2y+z)(x+y-2z)分之（y-x)(z-x) + (x+y-2z)(y+z-2x)分之(z-y)(x-y) + (y+z-2z)(x-2y+z)分之（x-z)(y-z)=?第三部分那个是 （y+z-2x)(x-2y+z)分之（x-z)(y-z)