设z=sin(x-y)求dz| x=1 y=1时的全微分
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设z=sin(x-y)求dz| x=1 y=1时的全微分
设z=sin(x-y)求dz| x=1 y=1时的全微分
设z=sin(x-y)求dz| x=1 y=1时的全微分
∂z/∂x=cos(x-y)
∂z/∂y=-cos(x-y)
=>
dz=∂z/∂x dx+∂z/∂y dy=cos(x-y)[dx-dy)
dz| (x=1 y=1)=dx-dy
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