已知:1/a+1/b=1/(a+b),则(b/a)+(a/b)的值等于?

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已知:1/a+1/b=1/(a+b),则(b/a)+(a/b)的值等于?
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已知:1/a+1/b=1/(a+b),则(b/a)+(a/b)的值等于?
已知:1/a+1/b=1/(a+b),则(b/a)+(a/b)的值等于?

已知:1/a+1/b=1/(a+b),则(b/a)+(a/b)的值等于?
1/a+1/b=1/(a+b)
(b+a)/ab=1/(a+b)
(a+b)^2=ab
a^2+2ab+b^2=ab
a^2+b^2=-ab
所以 (b/a)+(a/b)
=(b^2+a^2)/ab
=-ab/ab
=-1


因为:1/a+1/b=1/(a+b),所以:(a+b)^2=ab,即:a^2+b^2=-ab
所以:(a^2+b^2)/ab=-1,即:a/b+b/a=-1

1/a+1/b=1/(a+b)
(a+b)/ab=1/(a+b)
(a+b)²/ab=1
(a²+b²)/ab=-1
(b/a)+(a/b)=-1

b/a + a/b =
= (b^2 + a^2)/(ab)
= [(a+b)^2 - 2ab]/(ab)
= (ab - 2ab)/(ab)
= -ab/(ab)
= -1

1/a+1/b=1/(a+b)
(a+b)/ab=1/(a+b)
(a+b)²=ab
a²+b²+2ab=ab
两边同时除以ab
a/b+b/a+2=1
a/b+b/a=-1