求函数y=√-X²+2x+3的单调增区间y=√(-x²+2x+3)的定义域为:-x²+2x+3≥0x²-2x-3≤0 =>1≤x≤3 这步我明白.-1≤x≤3 ,到这,这-1是怎么来的?
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![求函数y=√-X²+2x+3的单调增区间y=√(-x²+2x+3)的定义域为:-x²+2x+3≥0x²-2x-3≤0 =>1≤x≤3 这步我明白.-1≤x≤3 ,到这,这-1是怎么来的?](/uploads/image/z/5303160-0-0.jpg?t=%E6%B1%82%E5%87%BD%E6%95%B0y%EF%BC%9D%E2%88%9A-X%26%23178%3B%2B2x%2B3%E7%9A%84%E5%8D%95%E8%B0%83%E5%A2%9E%E5%8C%BA%E9%97%B4y%3D%E2%88%9A%28-x%26%23178%3B%2B2x%2B3%29%E7%9A%84%E5%AE%9A%E4%B9%89%E5%9F%9F%E4%B8%BA%EF%BC%9A-x%26%23178%3B%2B2x%2B3%E2%89%A50x%26%23178%3B-2x-3%E2%89%A40+%3D%3E1%E2%89%A4x%E2%89%A43+%E8%BF%99%E6%AD%A5%E6%88%91%E6%98%8E%E7%99%BD.-1%E2%89%A4x%E2%89%A43+%2C%E5%88%B0%E8%BF%99%2C%E8%BF%99-1%E6%98%AF%E6%80%8E%E4%B9%88%E6%9D%A5%E7%9A%84%3F)
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求函数y=√-X²+2x+3的单调增区间y=√(-x²+2x+3)的定义域为:-x²+2x+3≥0x²-2x-3≤0 =>1≤x≤3 这步我明白.-1≤x≤3 ,到这,这-1是怎么来的?
求函数y=√-X²+2x+3的单调增区间
y=√(-x²+2x+3)的定义域为:
-x²+2x+3≥0
x²-2x-3≤0 =>1≤x≤3 这步我明白.-1≤x≤3 ,到这,这-1是怎么来的?
求函数y=√-X²+2x+3的单调增区间y=√(-x²+2x+3)的定义域为:-x²+2x+3≥0x²-2x-3≤0 =>1≤x≤3 这步我明白.-1≤x≤3 ,到这,这-1是怎么来的?
这个的话是这样的: x^-2x-3
啊,这个问题没目标,x²-2x-3≤0 <=>(x-3)(x+1)≤0,不就是 -1≤x≤3 吗