(1)已知x=1\2(√11+√7),y=1\2(√11-√7),求x²-xy+y²的值(2)已知x=2-√2,求(1\x²-2x-1\x²-4x+4)除以2\x²-2x的值明天8点之前要用
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![(1)已知x=1\2(√11+√7),y=1\2(√11-√7),求x²-xy+y²的值(2)已知x=2-√2,求(1\x²-2x-1\x²-4x+4)除以2\x²-2x的值明天8点之前要用](/uploads/image/z/5321077-61-7.jpg?t=%EF%BC%881%EF%BC%89%E5%B7%B2%E7%9F%A5x%3D1%5C2%28%E2%88%9A11%2B%E2%88%9A7%29%2Cy%3D1%5C2%28%E2%88%9A11-%E2%88%9A7%29%2C%E6%B1%82x%26%23178%3B-xy%2By%26%23178%3B%E7%9A%84%E5%80%BC%EF%BC%882%EF%BC%89%E5%B7%B2%E7%9F%A5x%3D2-%E2%88%9A2%2C%E6%B1%82%EF%BC%881%5Cx%26%23178%3B-2x-1%5Cx%26%23178%3B-4x%2B4%EF%BC%89%E9%99%A4%E4%BB%A52%5Cx%26%23178%3B-2x%E7%9A%84%E5%80%BC%E6%98%8E%E5%A4%A98%E7%82%B9%E4%B9%8B%E5%89%8D%E8%A6%81%E7%94%A8)
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