已知5x²+4x-2xy+y²+1=0,求x,y的值
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已知5x²+4x-2xy+y²+1=0,求x,y的值
已知5x²+4x-2xy+y²+1=0,求x,y的值
已知5x²+4x-2xy+y²+1=0,求x,y的值
原式=x²-2xy+y²+4x²+4x+1
=(x-y)²+(2x+1)²
所以(x-y)²+(2x+1)²=0