ABC中,AC=4,AD是∠BAC的角分线,BD=2,AD的垂直平分线EF交直线BC于点F,交AD于点E,交AC于M,AF=6,AM=____.着急
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![ABC中,AC=4,AD是∠BAC的角分线,BD=2,AD的垂直平分线EF交直线BC于点F,交AD于点E,交AC于M,AF=6,AM=____.着急](/uploads/image/z/5336200-64-0.jpg?t=ABC%E4%B8%AD%2CAC%3D4%2CAD%E6%98%AF%E2%88%A0BAC%E7%9A%84%E8%A7%92%E5%88%86%E7%BA%BF%2CBD%3D2%2CAD%E7%9A%84%E5%9E%82%E7%9B%B4%E5%B9%B3%E5%88%86%E7%BA%BFEF%E4%BA%A4%E7%9B%B4%E7%BA%BFBC%E4%BA%8E%E7%82%B9F%2C%E4%BA%A4AD%E4%BA%8E%E7%82%B9E%2C%E4%BA%A4AC%E4%BA%8EM%2CAF%3D6%2CAM%3D____.%E7%9D%80%E6%80%A5)
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ABC中,AC=4,AD是∠BAC的角分线,BD=2,AD的垂直平分线EF交直线BC于点F,交AD于点E,交AC于M,AF=6,AM=____.着急
ABC中,AC=4,AD是∠BAC的角分线,BD=2,AD的垂直平分线EF交直线BC于点F,交AD于点E,交AC于M,AF=6,AM=____.着急
ABC中,AC=4,AD是∠BAC的角分线,BD=2,AD的垂直平分线EF交直线BC于点F,交AD于点E,交AC于M,AF=6,AM=____.着急
连接ED,DM,设AM=X,
显然AEDM是菱形,所以
AE=DE=DM=AM=X
DF=AF=6
DM平行BE,
DF/BF=DM/E=6/8=X/BE
BE=4X/3
AB=7X/3
BE/AB=DE/AC
(4/3X)/(7X/3)=X/4
X=16/7
所以AM=16/7