如图,在平面直角坐标系中,直线y=x+6与x轴交于A,与y轴交于B,BC⊥AB交x轴于C如下图,D为OA延长线上一点,以BD为直角边做等腰直角三角形BDE,连接EA,并延长EA交y轴于点H.求直线EA的解析式
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![如图,在平面直角坐标系中,直线y=x+6与x轴交于A,与y轴交于B,BC⊥AB交x轴于C如下图,D为OA延长线上一点,以BD为直角边做等腰直角三角形BDE,连接EA,并延长EA交y轴于点H.求直线EA的解析式](/uploads/image/z/5344383-39-3.jpg?t=%E5%A6%82%E5%9B%BE%2C%E5%9C%A8%E5%B9%B3%E9%9D%A2%E7%9B%B4%E8%A7%92%E5%9D%90%E6%A0%87%E7%B3%BB%E4%B8%AD%2C%E7%9B%B4%E7%BA%BFy%3Dx%2B6%E4%B8%8Ex%E8%BD%B4%E4%BA%A4%E4%BA%8EA%2C%E4%B8%8Ey%E8%BD%B4%E4%BA%A4%E4%BA%8EB%2CBC%E2%8A%A5AB%E4%BA%A4x%E8%BD%B4%E4%BA%8EC%E5%A6%82%E4%B8%8B%E5%9B%BE%2CD%E4%B8%BAOA%E5%BB%B6%E9%95%BF%E7%BA%BF%E4%B8%8A%E4%B8%80%E7%82%B9%2C%E4%BB%A5BD%E4%B8%BA%E7%9B%B4%E8%A7%92%E8%BE%B9%E5%81%9A%E7%AD%89%E8%85%B0%E7%9B%B4%E8%A7%92%E4%B8%89%E8%A7%92%E5%BD%A2BDE%2C%E8%BF%9E%E6%8E%A5EA%2C%E5%B9%B6%E5%BB%B6%E9%95%BFEA%E4%BA%A4y%E8%BD%B4%E4%BA%8E%E7%82%B9H.%E6%B1%82%E7%9B%B4%E7%BA%BFEA%E7%9A%84%E8%A7%A3%E6%9E%90%E5%BC%8F)
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