化简:2cos4X+1/2×sin22X-cos2X 

来源:学生作业帮助网 编辑:作业帮 时间:2024/10/20 01:45:03
化简:2cos4X+1/2×sin22X-cos2X 
x){3{f%Dh^gd 1PS643I*' AΆ4jkmWhƂiiԁ2&eF`UцpXdpa} F6yv a

化简:2cos4X+1/2×sin22X-cos2X 
化简:2cos4X+1/2×sin22X-cos2X
 

化简:2cos4X+1/2×sin22X-cos2X 
2cos4X+1/2×sin22X-cos2X
=2*[2(cos2x)^2-1]+1/2*(sin2x)^2-cos2x
=4(cos2x)^2-2+1/2*[1-(cos2x)^2]-cos2x
=7(cos2x)^2/2-cos2x-3/2