求x趋于π/3时,[sin(x-π/3)]/1-2cosx的极限不要罗比达法则.告诉我思路就行.

求x趋于2,3,4,n时(x-x^3)/sinπx的极限, 求(sin^3x)/(tan(x^3))x趋于0时的极限如题 lim[1+sin(xy)]^(y/x)x趋于0 y趋于π,求极限 求Lim (2sin^n x+3cos^n x)∕(sin^n x+cos^n x) ,0≤x≤π/2n趋于无穷大 求 lim(tan x-sin x)/(sin x)^3 x趋于0的极限值详细步骤 求极限lim[sin(x^3)/x(x-ln(1+sinx))] x趋于0lim[sin(x^3)/x(x-ln(1+sinx))] x趋于0 求极限x^3*（cos x + sin x）/2^x,x趋于无穷 lim x趋于0 （x-sin x）/x^3 求x趋于π/3时,[sin(x-π/3)]/1-2cosx的极限不要罗比达法则.告诉我思路就行. 求极限lim(x趋于0时)sin(sinx)/x 当x趋于0,y趋于0时.求sin(x-y)/(x+y)极限? [x*sin(3/x)]的极限,x趋于正无穷 求极限((1-根号下x^2+1)/x^3y^2)sin(xy),当x,y趋于0时 lim[sin(x-3)]/√(1+x) -2 x趋于3求极限 急 求极限:lim(x趋于0)(e^sin^3x-1)/x(1-cosx), lim x趋于π sin{2(X-π)/(X-π)}求极限lim x趋于π {sin2(X-π)/(X-π)}求极限 求 lim (sin x)^3/ (tan x-sin x) 当x趋于0的极限值好吧，我会了、、、 sin(1/x) 的极限,x趋于(2/π)